Hey guys, I have a professor at college who assigns labs without EVER teaching the subject. This lab we were supposed to construct a traffic light for a "main street" that is intersected by a "cross street". The light goes yellow asynchronously when an emergency vehicle comes from the cross street, and stays yellow for 1 clock after, followed by red for 2 clocks and back to green. It is also supposed to check every 5 cycles whether there is a car waiting at the cross street and if there is, it goes yellow for 1 cycle then red for 2, then back to green again. I did all that fine and I even constructed my own components using vhdl, but now they are asking me to create a second design using a 2865 EEPROM by hand. I know what an eeprom is, I do not know how it works, all I know is that the 2865 has 13 addresses and 8 outputs, I don't even know how the outputs are selected. Can anyone enlighten me? Sorry, I have to implement it using hand drawn gates....at least to my understanding I do (the professor explains nothing! and TAs dont respond to emails), but I don't see why I couldnt just write A0=(whatever) A1=(whatever). I do have a logic table because I essentially created the device before using 3 d flip flips and two sets of combinational logic. (Total amount of states equates to 7, so I only needed 3) So I used an ASM table to try and help me out, which it did. I just have no idea how the eeprom works though, I mean I originally thought it was just a big decoder, but I don't even know anymore. All I know is that the lowest address is o/o/o/o in hex and 1/f/f/f is the highest but I don't know what that means. does 0/0/0/0 select d0? and if 1/f/f/f is the highest, what output does that goe too since there are only 8 outputs (1000 base 2)